Calculate the magnetic induction at the centre of a coil bent in the form of a square of side 10 cm carrying a current of 10 A.
Two particles A and B of masses m and 2m have charges q and 2q respectively. Both these particles moving with velocities v1 and v2 respectively in the same direction enter the same magnetic field B acting normally to their direction of motion. If the two forces FA and FB acting on them are in the ratio 1 : 2, find the ratio of their velocities.
A rectangular coil of sides l and b carrying a current I is subjected to a uniform magnetic field B acting perpendicular to its plane.
Obtain the expression for the torque acting on the rectangular coil.
A square loop of sides 5 cm carrying a current of 0.2 A in the clockwise direction is placed at a distance of 10 cm from an infinitely long wire carrying a current of 1 A as shown.
Calculate the resultant magnetic force acting on the loop.
Calculate the torque, if any, acting on the loop.
In a moving coil galvanometer, the deflecting torque acting on the coil is related to the current I flowing through it as:
Using Biot-Savart's law, derive the expression for the magnitude of the magnetic field at the centre of a circular loop of radius r carrying a steady current I.
Draw the field lines due to the current loop.
State Biot-Savart law expressing it in vector form.
Use it to obtain the magnetic field, at an axial point, distant r from the centre of a circular coil of radius a carrying a current I.
Hence, compare the magnitudes of the magnetic field of this coil at the centre and at an axial point for which
A particle of charge q and mass m starts moving with uniform velocity .
Specify the direction of magnetic field which should be set up in the region so that the particle moves straight undeviated.
Specify the direction of magnetic field which should be set up in the region so that the particle moves in a circle.
Justify your answers.
20 amp current is flowing in a long straight wire. The intensity of the magnetic field at a distance of 10 cm from the wire will be: