Coordinate Geometry, also known as Analytic Geometry, is a branch of mathematics that uses algebraic equations to describe geometric properties and relationships. It plays a crucial role in the JEE Main Mathematics syllabus, providing a foundation for understanding various geometric concepts through algebraic methods. This study note will cover essential topics, breaking down complex ideas into digestible sections and providing examples to enhance understanding.
The Cartesian coordinate system is a two-dimensional plane defined by two perpendicular axes: the x-axis (horizontal) and the y-axis (vertical). The point where these axes intersect is called the origin, denoted by $(0,0)$.
Example
Example: The point $(3, 4)$ lies 3 units to the right of the origin and 4 units above the origin.
The distance between two points $(x_1, y_1)$ and $(x_2, y_2)$ in the Cartesian plane is given by: $$ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} $$
Example
Example: The distance between the points $(1, 2)$ and $(4, 6)$ is: $$ d = \sqrt{(4 - 1)^2 + (6 - 2)^2} = \sqrt{9 + 16} = 5 $$
The section formula determines the coordinates of a point dividing a line segment joining two points $(x_1, y_1)$ and $(x_2, y_2)$ in the ratio $m:n$.
Tip
For internal division, remember to use the sum of the ratios ($m+n$) in the denominator. For external division, use the difference ($m-n$).
The slope (or gradient) of a line is a measure of its steepness and is defined as the ratio of the vertical change to the horizontal change between two points on the line.
$$ m = \frac{y_2 - y_1}{x_2 - x_1} $$
Several forms of the equation of a line are used in coordinate geometry:
Example
Example: Find the equation of a line passing through the points $(1, 2)$ and $(3, 4)$.
Using the two-point form: $$ y - 2 = \frac{4 - 2}{3 - 1}(x - 1) \Rightarrow y - 2 = x - 1 \Rightarrow y = x + 1 $$
The angle $\theta$ between two lines with slopes $m_1$ and $m_2$ is given by: $$ \tan \theta = \left| \frac{m_2 - m_1}{1 + m_1 m_2} \right| $$
Note
If the lines are perpendicular, $m_1 m_2 = -1$. If they are parallel, $m_1 = m_2$.
The standard form of the equation of a circle with center $(h, k)$ and radius $r$ is: $$ (x - h)^2 + (y - k)^2 = r^2 $$
The general form of a circle's equation is: $$ x^2 + y^2 + 2gx + 2fy + c = 0 $$ where the center is $(-g, -f)$ and the radius is $\sqrt{g^2 + f^2 - c}$.
Example
Example: Find the center and radius of the circle given by the equation $x^2 + y^2 - 4x + 6y - 12 = 0$.
Rewriting in standard form: $$ (x - 2)^2 + (y + 3)^2 = 25 $$ The center is $(2, -3)$ and the radius is $5$.
A parabola is a set of points equidistant from a fixed point (focus) and a fixed line (directrix).
For the parabola $y^2 = 4ax$:
Example
Example: Find the focus and directrix of the parabola $y^2 = 12x$.
Here, $4a = 12 \Rightarrow a = 3$. Thus:
An ellipse is the set of points where the sum of distances from two fixed points (foci) is constant.
For the ellipse $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$:
Example
Example: Find the foci and eccentricity of the ellipse $\frac{x^2}{16} + \frac{y^2}{9} = 1$.
Here, $a^2 = 16$ and $b^2 = 9 \Rightarrow c = \sqrt{16 - 9} = \sqrt{7}$. Thus:
A hyperbola is the set of points where the difference of distances from two fixed points (foci) is constant.
For the hyperbola $\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$:
Example
Example: Find the foci and asymptotes of the hyperbola $\frac{x^2}{9} - \frac{y^2}{16} = 1$.
Here, $a^2 = 9$ and $b^2 = 16 \Rightarrow c = \sqrt{9 + 16} = 5$. Thus:
Coordinate Geometry is a powerful tool that bridges algebra and geometry, allowing for the analysis and solution of complex geometric problems using algebraic methods. Mastery of the concepts in this study note will provide a solid foundation for tackling related problems in the JEE Main Mathematics syllabus.